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May 99 Challenge

Volume Number: 15 (1999)
Issue Number: 5
Column Tag: Programmer's Challenge

May 99 Challenge

by Bob Boonstra, Westford, MA


Every once in a while, good fortune not only comes your way, but actually reaches out of your computer monitor, and grabs you by the throat. I felt a little like that while reading a recent issue of TidBITS. In it was a column by Rick Holzgrafe reflecting on the increasing speed of computers, in which Rick described a program he wrote for a PDP-11/60 to solve a word puzzle. The idea behind the puzzle was to take a phrase and map it onto a rectangular grid, with the objective being to map the phrase into a rectangle of the smallest possible area. The word puzzle looked like a good idea for a Challenge, and Rick and TidBITS agreed to let me use it.

In more detail, the puzzle works like this. To start, you are given a null-terminated string consisting of printable characters. You process the characters in order, ignoring any non-alphabetic characters and ignoring case. The first alphabetic character can be mapped to any square in the grid. The next letter can be mapped to any adjacent square, where adjacent is any of the eight neighboring squares in a horizontal, vertical, or diagonal direction. You may reuse a square if it is adjacent and already has the letter you are mapping. If the same letter occurs twice in a row in the input string, the letters must still be mapped to adjacent (but distinct) squares.

The prototype for the code you should write is:

#if defined(__cplusplus)
extern "C" {

typedef struct GridPoint {
   long x;
   long y;
} GridPoint;

void Piper (
   char *s,
   GridPoint pt[]

#if defined(__cplusplus)

For example, your Piper routine might be provided with the string:

            How much wood would a woodchuck chuck if a woodchuck 
            could chuck wood?

You might place the letters of that string into a 4x14 rectangle like:

                  ULD  ADLU
                K   WO

Or, you might compact them into an 4x4 rectangle:


You must return the GridPoint coordinates of where each character is mapped, with pt[i] containing the coordinates of input character s[i]. The origin of your coordinate system should be the cell where the first character is placed. The winner will be the solution that stores the input string in a rectangle of minimal area. Note that you are minimizing rectangle area, not the number of occupied squares. A time penalty of 1% for each second of execution time will be added

This will be a native PowerPC Challenge, using the latest CodeWarrior environment. Solutions may be coded in C, C++, or Pascal.

Three Months Ago Winner

The February Challenge invited readers to write a player for the game of Chinese Checkers. Played on a hexagonal board with six appended triangles, Chinese Checkers pits between 2 and 6 players against one another, with the objective being to move one's pieces from the home triangle to the opposite triangle. In the traditional game, the home triangles are usually 3 or 4 positions on a side; the Challenge extended the game to triangles of up to 64 positions. Pieces can either be moved to an immediately adjacent position or jumped over an adjacent piece. A single piece is permitted to make a sequence of jumps in a single move.

As simple as the game sounds, readers found it to be very difficult, so difficult that no solutions were submitted for the Chinese Checkers Challenge. Which left Yours Truly in something of a difficult spot. I could stop the column at this point, which wouldn't be very interesting for readers, not to mention not very satisfying for the magazine. Or I could write a solution for the Challenge myself, something I haven't done since I retired from Competition four plus years ago. Somewhat against my better judgement, I selected the latter option.

The first thing I noticed in solving the Challenge was that the board coordinate system specified in the problem wasn't very useful in generating a solution. I needed a coordinate system that could be easily rotated in 60-degree increments, enabling my solution to play any of the six possible player positions. After some thought, I came up with a more symmetric coordinate system, called CanonPosition in the code, along with conversion routines ConvertPositionToCanonPosition and ConvertCanonPositionToPosition. The commentary in the code illustrates the coordinate system for a board of size 4. Then I needed a way to evaluate board positions. I decided on a simple metric that summed the distances of all pieces from the apex of their goal triangle. That metric could be improved upon by taking possible jump moves into account. The solution starts by computing all possible moves for our player. It then tries each of those moves, and then recursively calls MakeNextMove to process the next player. It computes and tries all moves for that player, and recurses for the next player. Recursion terminates when kMaxPlys turns have been taken for all players. Positions are evaluated using a min-max technique, where each player selects the position that maximizes his position relative to the best position of the other players.

The code could be improved in many ways. Instead of trying all possible positions, it could prune some obviously bad moves in the backward direction. This is complicated by the fact that some good jump multi-moves can include individual jumps that appear to be moving backward. The code might also be improved by evaluating moves by progressive deepening, rather than the depth-first search currently used, and by ordering move evaluation based on the scores at the prior depth. This technique is used in chess programs to prune the move tree to a manageable size. These and other optimizations are left to the reader. :-)

Remember, you can't win if you don't play. To ensure that you have as much time as possible to solve the Challenge, subscribe to the Programmer's Challenge mailing list. To subscribe, see the Challenge web page at <>. The Challenge is sent to the list around the 12th of the month before the solutions are due, often in advance of when the physical magazine is delivered.

Here is our sample Chinese Checkers solution:

Chinese Checkers.c
Copyright © 1999 J. Robert Boonstra

*  Example solution for the February 1999 Programmer's Challenge
 *  This solution is provided because no solutions were submitted
 *  for the ChineseCheckers Challenge.  This solution leaves a 
 *  great deal to be desired: it is not optimized, it does not 
 *  prune prospective moves efficiently, and it does not employ
 *  any of the classic alpha-beta techniques for efficiently
 *  selecting a move.

#include <stdio.h>
#include <stdlib.h>
#include <Quickdraw.h>
#include "ChineseCheckers.h"

/* Position coordinates specified in problem (size==4)

  0:                           0
  1:                         0   1 
  2:                      -1   0   1 
  3:                    -1   0   1   2
  4:  -6  -5  -4  -3  -2  -1   0   1   2   3   4   5   6 
  5:    -5  -4  -3  -2  -1   0   1   2   3   4   5   6
  6:      -5  -4  -3  -2  -1   0   1   2   3   4   5  
  7:        -4  -3  -2  -1   0   1   2   3   4   5
  8:          -4  -3  -2  -1   0   1   2   3   4  
  9:        -4  -3  -2  -1   0   1   2   3   4   5
 10:      -5  -4  -3  -2  -1   0   1   2   3   4   5  
 11:    -5  -4  -3  -2  -1   0   1   2   3   4   5   6
 12:  -6  -5  -4  -3  -2  -1   0   1   2   3   4   5   6 
 13:                    -1   0   1   2
 14:                      -1   0   1 
 15:                         0   1 
 16:                           0

#define kMaxPlys 1
#define kEmpty -1

/* CanonPosition uses units with (0,0) at the middle of the board */
typedef struct CanonPosition {
   long row;
   long col;
} CanonPosition;

/* Canonical position coordinates (size==4)

 -8:                           0
 -7:                        -1   1 
 -6:                      -2   0   2 
 -5:                    -3  -1   1   3
 -4: -12 -10  -8  -6  -4  -2   0   2   4   6   8  10  12 
 -3:   -11  -9  -7  -5  -3  -1   1   3   5   7   9  11
 -2:     -10  -8  -6  -4  -2   0   2   4   6   8  10  
 -1:        -9  -7  -5  -3  -1   1   3   5   7   9
  0:          -8  -6  -4  -2   0   2   4   6   8  
  1:        -9  -7  -5  -3  -1   1   3   5   7   9
  2:     -10  -8  -6  -4  -2   0   2   4   6   8  10  
  3:   -11  -9  -7  -5  -3  -1   1   3   5   7   9  11
  4: -12 -10  -8  -6  -4  -2   0   2   4   6   8  10  12 
  5:                    -3  -1   1   3
  6:                      -2   0   2 
  7:                        -1   1 
  8:                           0

/* PlayerPos is used to store the location of each of a players pieces */
typedef struct PlayerPos {
   CanonPosition pos;
} PlayerPos;

typedef char *CanonBoard;

static long myNumPlayers,myNumPieces,myIndex,myGameSize,
static PlayerPos *myPositions;

/* global board */
static CanonBoard myBoard;

/* moveIncrement is added to a CanonPosition to find the adjacent square in the
 * six possible directions 0..6, with 0==horizontal right, 1==down right, ...
 * 5==up right
static CanonPosition moveIncrement[6] = 
   { { 0, 2}, { 1, 1}, { 1,-1}, { 0,-2}, {-1,-1}, {-1, 1} };

/* macros to access the board */
#define CanonRowSize(size) (6*(size)+1)
#define CanonBoardPos(row,col) (3*(myGameSize) +    \
         (2*(myGameSize)+(row))*(CanonRowSize(myGameSize)) + (col))
#define CanonBoardVal(board,row,col)          \
#define IsEmpty(board,row,col)             \
         (kEmpty == board[CanonBoardPos(row,col)])

/* Convert coordinates from problem statement to canonical coordinates */
static CanonPosition ConvertPositionToCanonPosition (
            Position *pos, long size) {
   CanonPosition canon;
   canon.row = pos->row - 2 * size;
   if (pos->row == 2 * (int)(pos->row/2)) {
      canon.col = 2 * pos->col;
   } else {
      canon.col = 2 * pos->col - 1;
   return canon;

/* Convert canonical coordinates to coordinates from problem statement */
static Position ConvertCanonPositionToPosition (CanonPosition *canon, long size) {
   Position pos;
   pos.row = canon->row + 2 * size;
   if (canon->row == 2 * (int)(canon->row/2)) {
      pos.col = canon->col / 2;
   } else {
      pos.col = (canon->col + 1) / 2;
   return pos;

/* rotate board by posNum increments of player positions (60 degrees) */
static CanonPosition RotateCanonPosition0ToN(
         CanonPosition oldPos, long posNum) {
   CanonPosition newPos;
   while (posNum<0) posNum+=6;   /* normalize to 0..5 */
   while (posNum>5) posNum-=6;
   switch (posNum) {
   case 0:
      newPos.row = oldPos.row;
      newPos.col = oldPos.col;
   case 1:
      newPos.row = (oldPos.row + oldPos.col)/2;
      newPos.col = (oldPos.col - 3*oldPos.row)/2;
   case 2:
      newPos.row =  (oldPos.col - oldPos.row)/2;
      newPos.col = -(oldPos.col + 3*oldPos.row)/2;
   case 3:
      newPos.row = -oldPos.row;
      newPos.col = -oldPos.col;
   case 4:
      newPos.row = -(oldPos.row + oldPos.col)/2;
      newPos.col = -(oldPos.col - 3*oldPos.row)/2;
   case 5:
      newPos.row = -(oldPos.col - oldPos.row)/2;
      newPos.col =  (oldPos.col + 3*oldPos.row)/2;
   return newPos;

/* return the max column number in a given row */
static long MaxColInRow(long row, long size) {
   long maxCol;
   if (row<-size) {
      maxCol = row+2*size;
   } else if (row<0) {
      maxCol = 2*size-row;
   } else if (row<=size) {
      maxCol = row+2*size;
   } else /* if (row<=2*size) */ {
      maxCol = 2*size-row;
   return maxCol;

/* determine if a row,col coordinate represents a legal position */
static Boolean IsLegalPosition(CanonPosition *pos) {
   long maxCol;
   if ((pos->row<-2*myGameSize) || (pos->row>2*myGameSize)) 
         return false;
   if ((pos->row + pos->col) != 
               2 * (int)((pos->row + pos->col)/2)) 
      return false;
   maxCol = MaxColInRow(pos->row,myGameSize);
   if ((pos->col<-maxCol) || (pos->col>maxCol)) 
      return false;
   return true;

/* move a piece between positions from and to, does not check legality of move */
static void MoveFromTo(CanonBoard b,CanonPosition *from,CanonPosition *to,long newValue) {
   PlayerPos *p = &myPositions[newValue*myNumPieces];
   long oldValue = CanonBoardVal(b,from->row,from->col);
   int i;
   if (oldValue != newValue) {
      DebugStr("\p check err");
   if ( IsLegalPosition(from) && IsLegalPosition(to) ) {
      CanonBoardVal(b,from->row,from->col) = kEmpty;
      CanonBoardVal(b,to->row,to->col) = (char)newValue;
      for (i=0; i<myNumPieces; i++) {
         if (    (p[i].pos.row == from->row) && 
                     (p[i].pos.col == from->col)) {
            p[i].pos.row = to->row;
            p[i].pos.col = to->col;

/* return the distance of a given position from a goal postion for player 0 */
static long PositionDistFromGoal (const CanonPosition *a, const CanonPosition *goal) {
   long rowDelta,colDelta;
   rowDelta = a->row - goal->row;
   if (rowDelta<0) rowDelta = -rowDelta;
   colDelta = a->col - goal->col;
   if (colDelta<0) colDelta = -colDelta;
   if (rowDelta>=colDelta) return rowDelta;
   else return rowDelta + (colDelta-rowDelta)/2;

/* return the cumulative distance of a player from his goal postion */
static long PlayerDistFromGoal(long player) {
   long cumDist;
   int i;
   CanonPosition goal;
   PlayerPos *p = &myPositions[player*myNumPieces];
   goal.row = -2*myGameSize;
   goal.col = 0;
   goal = 
   for (i=0, cumDist=0; i<myNumPieces; i++) {
      CanonPosition *cp = &p[i].pos;
      long dist = PositionDistFromGoal(cp,&goal);
      cumDist += dist;
   return cumDist;

/* initialize the positions for a player at a given position */
static void InitPlayer(char *b,PlayerPos *piecePositions, long player, long position,long size) {
   CanonPosition pos,newPos;
   int col,maxCol,pieceCount;
   PlayerPos *piecePos;
   pieceCount = 0;
   for (maxCol=0; maxCol<size; maxCol++) {
      pos.row = -2*size+maxCol;
      maxCol = maxCol;
      for (col=-maxCol; col<=maxCol; col+=2) {
         pos.col = col;
         newPos = RotateCanonPosition0ToN(pos,position);
         CanonBoardVal(b,newPos.row,newPos.col) = (char)player;
   piecePos = &piecePositions[myNumPieces*player + pieceCount];
         piecePos->pos = newPos;

/* some variables to record the history of multi-jump moves, to
   prevent them from repeating infinitely */
static CanonPosition gMoveHistoryPos[6*64];
static long gMoveHistoryDirection[6*64];
static long gMoveHistoryCtr = -1;

/* Calculate a move for a given piece for a given player in a given moveDir.
 * Return true there is a legal move.
 * Return doneWithThisDirection==true if there are no more moves in this direction.
static Boolean CalcMove(
         CanonBoard b, long player, long pieceNum, long moveDir, 
         CanonPosition *p1, CanonPosition *p2, 
         Boolean *doneWithThisDirection, long iterationLimit) {
   Boolean legalMove = true;
   if (gMoveHistoryCtr<0) {
      PlayerPos *p = &myPositions[player*myNumPieces];
      *p2 = *p1 = p[pieceNum].pos;
      p2->row += moveIncrement[moveDir].row;
      p2->col += moveIncrement[moveDir].col;
      if (!IsLegalPosition(p2)) legalMove = false;
      else if (IsEmpty(b,p2->row,p2->col)) {
      } else {
         long oldVal = CanonBoardVal(b,p2->row,p2->col);
         p2->row += moveIncrement[moveDir].row;
         p2->col += moveIncrement[moveDir].col;
         if (!IsLegalPosition(p2)) legalMove = false;
         else if (IsEmpty(b,p2->row,p2->col)) {
            if (gMoveHistoryCtr>iterationLimit) 
                        DebugStr("\p limit exceeded");
            gMoveHistoryPos[++gMoveHistoryCtr] = *p1;
            gMoveHistoryDirection[gMoveHistoryCtr] = 6;
            gMoveHistoryPos[++gMoveHistoryCtr] = *p2;
            gMoveHistoryDirection[gMoveHistoryCtr] = -1;
         } else {
            legalMove = false;
   } else {
      CanonPosition pStart,pTemp;
      long newDir;
      pStart = pTemp = gMoveHistoryPos[gMoveHistoryCtr];
      while (   (gMoveHistoryCtr>=0) && 
                     (gMoveHistoryDirection[gMoveHistoryCtr]>=6) ) {
      if (gMoveHistoryCtr>0) {
         newDir = gMoveHistoryDirection[gMoveHistoryCtr];
         pTemp.row += moveIncrement[newDir].row;
         pTemp.col += moveIncrement[newDir].col;
         if (!IsLegalPosition(&pTemp)) legalMove=false;
         else if (IsEmpty(b,pTemp.row,pTemp.col)) legalMove=false;
         else {
            pTemp.row += moveIncrement[newDir].row;
            pTemp.col += moveIncrement[newDir].col;
            if (!IsLegalPosition(&pTemp)) legalMove=false;
            else if (!IsEmpty(b,pTemp.row,pTemp.col)) legalMove=false;
            else {
               int i;
               for (i=0; i<=gMoveHistoryCtr; i++)
                  if (   (pTemp.row == gMoveHistoryPos[i].row) && 
                           (pTemp.col == gMoveHistoryPos[i].col) )
               if (legalMove) {
                  gMoveHistoryDirection[++gMoveHistoryCtr] = -1;
                  gMoveHistoryPos[gMoveHistoryCtr] = pTemp;
                  *p1 = gMoveHistoryPos[0];
                  *p2 = pTemp;
      } else {
   *doneWithThisDirection = (gMoveHistoryCtr<0);
   return legalMove;

/* multiplier to determine how much storage to reserves for moves for each piece */
#define kMemAllocFudge 12

static long EnumerateMoves(CanonBoard b, long player, CanonPosition moveFrom[], CanonPosition moveTo[]) {
   long numMoves = 0;
   int piece,moveDir;
   Boolean legalMove,doneWithThisDirection;
   for (piece=0; piece<myNumPieces; piece++) {
      int pieceCounter=0;
      int firstPieceMoveIndex = numMoves;
      moveDir = 0;
      do {
         legalMove = CalcMove(b,player,piece,moveDir,
         if (doneWithThisDirection)
         if (!legalMove) continue;
         if (numMoves>=kMemAllocFudge*myNumPieces-1) {
            DebugStr("\pnumMoves limit exceeded");
         } else {
            int i;
            for (i=firstPieceMoveIndex; i<numMoves; i++)
               if ( (moveTo[i].row==moveTo[numMoves].row) && 
                   (moveTo[i].col==moveTo[numMoves].col) )
                     legalMove = false;
            if (!legalMove) continue;
      } while (moveDir<6);
   return numMoves;

 * Recursive routine to explore move tree.
 * MakeNextMove iterates over all possible moves for a player.
 * If ply limit is not yet reached, it recurses by calling for the next player.
 * Ply limit is decreased by 1 when the "me" player is called.
 * Recursion terminates when ply limit is reached.
 * Score is assigned on return based on the perspective of the player making the move.
 * Simple-minded score algorithm is used: 
 *   difference between player score and the best other player score, where
 *   a player's score is the number of spaces he is away from the final state
 * No alpha-beta pruning is employed - search is exhaustive.

static long MakeNextMove(CanonBoard b, long me, long player, long playerDistances[6], long numPlys,
   Boolean firstTime, CanonPosition *from, CanonPosition *to) {
   long theMove,nextPlayer,numMoves,
               bestScore=0x7FFFFFFF, myBestDistance=0x7FFFFFFF;
   CanonPosition pFrom,pTo,bestFrom,bestTo;
   int newPlys;
   CanonPosition *moveFrom,*moveTo;

   /* allocate storage for possible moves */
   moveFrom = (CanonPosition *)
   if (0==moveFrom) 
         DebugStr("\pproblem allocation moveFrom memory");
   moveTo = (CanonPosition *)
   if (0==moveTo) 
         DebugStr("\pproblem allocation moveTo memory");
   /* prime best move with starting move */
   bestFrom = *from;
   bestTo = *to;
   /* enumerate all legal moves for this player */
   numMoves = EnumerateMoves(b,player,moveFrom,moveTo);
   /* examine all of the enumerated moves */
   for (theMove=0; theMove<numMoves; theMove++) {
      long opponent,scoreDifference,minOpponentDistance,
      int thePlayer;
      pFrom = moveFrom[theMove];
      pTo = moveTo[theMove];
      if (firstTime) {
         *from = pFrom;
         *to = pTo;
      nextPlayer = (player+1)%myNumPlayers;
      newPlys = (player==me) ? numPlys-1 : numPlys;
      /* record move in the simulated board */
      myDistance = PlayerDistFromGoal(player);
      /* recurse if ply limit not reached */
      if ( (newPlys>=0) && (myDistance>myMinDist) ){
         /* MakeNextMove returns each player's distance from the goal in 
            returnedDistances, and the score from nextPlayer's perspective in 
            returnScore is ignored except by nonrecursive callers to MakeNextMove 
         long returnScore;
         returnScore = 
               MakeNextMove(b, me, nextPlayer, returnedDistances, 
                           newPlys, false, from, to);
      } else /*if (player==me)*/ {
         /* terminating recursion, calculate position values for each player */
         /* compute distances for all players */
         for (thePlayer=0; thePlayer<myNumPlayers; thePlayer++)
            returnedDistances[thePlayer] = 
      /* compute best opponent score from this player perspective */
      for (thePlayer=0,minOpponentDistance=0x7fffffff; 
                     thePlayer<myNumPlayers; thePlayer++) {
         if (   (thePlayer != player) && 
            (returnedDistances[thePlayer]<minOpponentDistance) ) 
            minOpponentDistance = returnedDistances[thePlayer];
      scoreDifference = 
      /* Save score if it is the best for this player.
         This move is best if
         (1) our distance from goal minus best opponents distance is smallest, or
         (2) goal distance difference is equal, but our absolute distance is smallest, or
         (3) goal distance difference is equal, and coin flip says pick this move 
                                          (commented out) */
      if ( (scoreDifference < bestScore) ||
          ((scoreDifference==bestScore) && 
                  (returnedDistances[player]<myBestDistance)) /*||
((scoreDifference==bestScore) && ((rand()&0x0080)==1))*/ ) {
         bestScore = scoreDifference;
         myBestDistance = returnedDistances[player];
         for (opponent=0; opponent<myNumPlayers; opponent++)
      playerDistances[opponent] = returnedDistances[opponent];
         bestFrom = pFrom;
         bestTo = pTo;
      /* reverse move to clear board for mext move */
   /* free dynamically allocated move storage */
   /* return best move */
   *from = bestFrom;
   *to = bestTo;

   return bestScore;

/* find best move for player me from this position on the board */
static long FindBestMove(CanonBoard b, long me, long numPlys, CanonPosition *from, CanonPosition *to) {
   long playerDistances[6];

   return MakeNextMove(b,me,me,playerDistances,numPlys,true,from,to);

void InitChineseCheckers(
   long numPlayers,      /* 2..6  */
   long gameSize, /* base of home triangle, 3..63, you have size*(size+1)/2 pieces */
   long playerPosition[6],   /* 0..5, entries 0..numPlayers-1 are valid */
   long yourIndex /* 0..numPlayers-1, your position is playerPosition[yourIndex] */
) {
   int i,numPositions;
   /* allocate memory for board */
   numPositions = 6*(1+gameSize)*4*(1+gameSize);
   myBoard = (char *)malloc(numPositions*sizeof(char));
   if (myBoard==0) DebugStr("\p could not allocate board");
   myNumPieces = gameSize*(gameSize+1)/2;
   myPositions = (PlayerPos *)
   if (myPositions==0) 
               DebugStr("\p could not allocate myPositions");

   /* copy parameters */
   for (i=0;i<6; i++) myPlayerPosition[i] = playerPosition[i];
   myIndex = yourIndex;
   myNumPlayers = numPlayers;
   myGameSize = gameSize;
   /* initialize board */
   for (i=0; i<numPositions; i++) myBoard[i] = kEmpty;
   for (i=0; i<numPlayers; i++) {
   /* calculate distance metric at goal position */
   for (i=1, myMinDist=0; i<gameSize; i++) myMinDist += i*(i+1);

void YourMove(
   Position *fromPos,   /* originating position */
   Position *toPos   /* destination position */
) {
   CanonPosition from,to;
   long numPlys = kMaxPlys;
   *fromPos = ConvertCanonPositionToPosition(&from,myGameSize);
   *toPos = ConvertCanonPositionToPosition(&to,myGameSize);

void OpponentMove(
   long opponent,   /* index in playerPosition[] of the player making move */
   Position fromPos,   /* originating position */
   Position toPos      /* destination position */
) {
   CanonPosition from,to;
   from = ConvertPositionToCanonPosition(&fromPos,myGameSize);
   to =   ConvertPositionToCanonPosition(&toPos,myGameSize);

void TermChineseCheckers(void) {
   free (myPositions);
   free (myBoard);

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Arq is super-easy online backup for Mac and Windows computers. Back up to your own cloud account (Amazon Cloud Drive, Google Drive, Dropbox, OneDrive, Google Cloud Storage, any S3-compatible server... Read more
Instaradio 7.1 - Listen to your favorite...
Instaradio is fast, and it could be the radio player you have been waiting for. Try the app thousands of people rely on for listening to radio. Features Listen to radio from all around the world... Read more

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Goat Simulator PAYDAY (Games)
Goat Simulator PAYDAY 1.0 Device: iOS Universal Category: Games Price: $4.99, Version: 1.0 (iTunes) Description: ** IMPORTANT - SUPPORTED DEVICES **iPhone 4S, iPad 2, iPod Touch 5 or better Goat Simulator: Payday is the most... | Read more »
Zombie Gunship Survival Beginner's...
The much anticipated Zombie Gunship Survival is here. In this latest entry in the Zombie Gunship franchise, you're tasked with supporting ground troops and protecting your base from the zombie horde. There's a lot of rich base building fun, and... | Read more »
Mordheim: Warband Skirmish (Games)
Mordheim: Warband Skirmish 1.2.2 Device: iOS Universal Category: Games Price: $3.99, Version: 1.2.2 (iTunes) Description: Explore the ruins of the City of Mordheim, clash with other scavenging warbands and collect Wyrdstone -... | Read more »
Mordheim: Warband Skirmish brings tablet...
Legendary Games has just launched Mordheim: Warband Skirmish, a new turn-based action game for iOS and Android. | Read more »
Magikarp Jump splashes onto Android worl...
If you're tired ofPokémon GObut still want something to satisfy your mobilePokémon fix,Magikarp Jumpmay just do the trick. It's out now on Android devices the world over. While it looks like a simple arcade jumper, there's quite a bit more to it... | Read more »
Purrfectly charming open-world RPG Cat Q...
Cat Quest, an expansive open-world RPG from former Koei-Tecmo developers, got a new gameplay trailer today. The video showcases the combat and exploration features of this feline-themed RPG. Cat puns abound as you travel across a large map in a... | Read more »
Jaipur: A Card Game of Duels (Games)
Jaipur: A Card Game of Duels 1.0 Device: iOS Universal Category: Games Price: $1.99, Version: 1.0 (iTunes) Description: ** WARNING: iPad 2, iPad Mini 1 & iPhone 4S are NOT compatible. ** *** Special Launch Price for a limited... | Read more »
Subdivision Infinity (Games)
Subdivision Infinity 1.03 Device: iOS Universal Category: Games Price: $2.99, Version: 1.03 (iTunes) Description: Launch sale! 40% Off! Subdivision Infinity is an immersive and pulse pounding sci-fi 3D space shooter. https://www.... | Read more »
Clash of Clans' gets a huge new upd...
Clash of Clans just got a massive new update, and that's not hyperbole. The update easily tacks on a whole new game's worth of content to the hit base building game. In the update, that mysterious boat on the edge of the map has been repaired and... | Read more »
Thimbleweed Park officially headed to iO...
Welp, it's official. Thimbleweed Park will be getting a mobile version. After lots of wondering and speculation, the developers confirmed it today. Thimbleweed Park will be available on both iOS and Android sometime in the near future. There's no... | Read more »

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Apple refurbished 13-inch MacBook Airs availa...
Apple has Certified Refurbished 2016 13″ MacBook Airs available starting at $849. An Apple one-year warranty is included with each MacBook, and shipping is free: - 13″ 1.6GHz/8GB/128GB MacBook Air: $... Read more
Apple restocks refurbished 11-inch MacBook Ai...
Apple has Certified Refurbished 11″ MacBook Airs (the latest models recently discontinued by Apple), available for up to $170 off original MSRP. An Apple one-year warranty is included with each... Read more
12-inch 1.2GHz Retina MacBooks on sale for up...
B&H has 12″ 1.2GHz Retina MacBooks on sale for up to $150 off MSRP. Shipping is free, and B&H charges NY & NJ sales tax only: - 12″ 1.2GHz Space Gray Retina MacBook: $1449.99 $150 off... Read more
15-inch 2.7GHz Silver Touch Bar MacBook Pro o...
MacMall has the 15-inch 2.7GHz Silver Touch Bar MacBook Pro (MLW82LL/A) on sale for $2569 as part of their Memorial Day sale. Shipping is free. Their price is $230 off MSRP. Read more
Free Tread Wisely Mobile App Endorsed By Fath...
Just in time for the summer driving season, Cooper Tire & Rubber Company has announced the launch of a new Tread Wisely mobile app. Designed to promote tire and vehicle safety among teens and... Read more
Commercial Notebooks And Detachable Tablets W...
Worldwide shipments of personal computing devices (PCDs), comprised of traditional PCs (a combination of desktop, notebook, and workstations) and tablets (slates and detachables), are forecast to... Read more
Best value this Memorial Day weekend: Touch B...
Apple has Certified Refurbished 2016 15″ and 13″ MacBook Pros available for $230 to $420 off original MSRP. An Apple one-year warranty is included with each model, and shipping is free: - 15″ 2.6GHz... Read more
13-inch MacBook Airs on sale for up to $130 o... has 13″ MacBook Airs on sale for up to $130 off MSRP including free shipping: - 13″ 1.6GHz/128GB MacBook Air (sku MMGF2LL/A): $869.99 $130 off MSRP - 13″ 1.6GHz/256GB MacBook Air (sku... Read more
2.8GHz Mac mini available for $973 with free...
Adorama has the 2.8GHz Mac mini available for $973, $16 off MSRP, including a free copy of Apple’s 3-Year AppleCare Protection Plan. Shipping is free, and Adorama charges sales tax in NY & NJ... Read more
15-inch 2.2GHz Retina MacBook Pro on sale for...
Amazon has 15″ 2.2GHz Retina MacBook Pros (MJLQ2LL/A) available for $1749.99 including free shipping. Apple charges $1999 for this model, so Amazon’s price is represents a $250 savings. Note that... Read more

Jobs Board

*Apple* Media Products - Commerce Engineerin...
Apple Media Products - Commerce Engineering Manager Job Number: 57037480 Santa Clara Valley, California, United States Posted: Apr. 18, 2017 Weekly Hours: 40.00 Job Read more
*Apple* Mac and Mobility Engineer - Infogrou...
Title: Apple Mac and Mobility Engineer Location: Portland, OR Area Type: 12 month contract Job: 17412 Here's a chance to take your skills to the limit, learn new Read more
*Apple* Retail - Multiple Positions, White P...
Sales Specialist - Retail Customer Service and Sales Transform Apple Store visitors into loyal Apple customers. When customers enter the store, you're also the Read more
Best Buy *Apple* Computing Master - Best Bu...
**509110BR** **Job Title:** Best Buy Apple Computing Master **Location Number:** 000048-Topeka-Store **Job Description:** **What does a Best Buy Apple Computing Read more
*Apple* Retail - Multiple Positions - Apple,...
Job Description: Sales Specialist - Retail Customer Service and Sales Transform Apple Store visitors into loyal Apple customers. When customers enter the store, Read more
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